math
posted by mario .
drama club sold adult tickets for $8 and kid tickets for $5. for the final performance a total of 226 tickets were sold for a total of $1670. how many adult tickets were sold for the performance?
X = # of adult tickets
Y = # of kid tickets
X + Y = 226
8X + 5Y = 1670
Solve those two equations in two unknowns. One way would be to use substitution. (Insert 226  X in place of Y in the second equation).

Let x = adult's tickets
y = children's tickets
Equation Insert x value in
1. x + y = 226 first equation
180 + y=226
2. 8x + 5y = 1670 y=226180
By substitution, y=46
x=180,y=46 Ans.
y = 226226x
2. 8x + 5(226x)=1670 multiply
8x + 1130  5x=1670 cancellation
8x5x=16701130
3x=540
x=180 continue above: 
Let x = adult's tickets
y = children's tickets
Equation Insert x value in
1. x + y = 226 first equation
180 + y=226
2. 8x + 5y = 1670 y=226180
By substitution, y=46
x=180,y=46 Ans.
y = 226226x
2. 8x + 5(226x)=1670 multiply
8x + 1130  5x=1670 cancellation
8x5x=16701130
3x=540 divide
x=180 continue above:
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