Two forces act on a 0.200 kg ant: F1 =(3.00i - 8.00j)N and F2=(5.00i + 3.00j)N.
Express the net acceleration of the ant in unit vector notation.
The resultant force is 8.00 i - 5.00 j Newtons. Divide that by the mass (0.2 kg) for the acceleration vector, in m/s^2.
To find the net acceleration of the ant, we need to calculate the resultant force and then divide it by the mass of the ant.
Given that the resultant force is 8.00 i - 5.00 j Newtons, we can express it as a vector:
R = 8.00 i - 5.00 j N
and the mass of the ant is 0.200 kg.
To find the net acceleration, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:
Fnet = m * a
In this case, the net force is the resultant force, R.
So, we can rewrite the equation as:
R = m * a
To find the acceleration vector, we need to divide the resultant force vector by the mass:
a = R / m
Substituting the values, we have:
a = (8.00 i - 5.00 j N) / 0.200 kg
Dividing each component of the resultant force vector by the mass, we get:
a = (8.00 / 0.200) i - (5.00 / 0.200) j m/s^2
Simplifying the equation, we get:
a = 40 i - 25 j m/s^2
Therefore, the net acceleration of the ant, expressed in unit vector notation, is 40 i - 25 j m/s^2.