Math

posted by .

A=1/2H(B+b) Solve for H

Let's start by getting rid of the fraction.

Multiply both sides by 2 (whatever operation you do to one side of an equation you must do to the other side as well):

2(A) = 2[1/2H(B+b)]

2A = H(B+b)

Now divide both sides by (B+b) and end up with this:

2A/(B+b) = H

I hope this will help.

  • Math -

    please solve -20+2h=20

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Variable

    SOLVING EQUATIONS WITH THE VARIABLE ON BOTH SIDES Solve the equation. Then check your solution. 4x-9 = 7x+12 Just remember that one can add, subtract, multiply, divide, etc but whatever is done to one side must be done to the other …
  2. algebra

    logarithms Solve the following equations 3^x-2=6 Add 2 to both sides of the equation to start. Whatever operation you do to one side of an equation you must do to the other side as well. 3^x - 2 + 2 = 6 + 2 3^x = 8 Changing to logs: …
  3. Algebra

    - 20> 8 +7a Solve inequalities like you would an equation, EXCEPT if you multiply or divide by a negative number, reverse the inequality sign. Let's look at your problem: - 20 > 8 + 7a First subtract 8 from both sides (whatever …
  4. algebra3

    which inequality is tge solution of 6x negative 3 greater than or = to 7 plus 4x?
  5. Pre Cal

    6-x=2x+9 If you are to solve the equation for x, first try to get the variable on one side of the equation. Let's subtract 2x from both sides to start (whatever operation you do to one side of an equation you must do to the other side …
  6. MATH PLEASE CHECK IT!!2

    m-2/m-5*m+5/m-2=-1 If your problem is this: (m - 2)/(m - 5) * (m + 5)/(m - 2) = -1 (m - 2) cancels out in both the numerator and denominator on the left-hand side since you are multiplying. That leaves us with this: (m + 5)/(m - 5) …
  7. math--pre alg

    not sure i did right 3(f+2)+9=13+5f 3f+6+9 = 13+5f +9 3F+15 = 12+5F GOT MIXED UP SOMWERE HELP 3f +6 +9 = 13 + 5f 3f + 15 = 13 + 5f 2f = 2 f = 1 drwls is correct You are doing OK up to this point: 3f + 6 + 9 = 13 + 5f Now combine any …
  8. Math

    q + 13 = 120 __ 8 I'm going to assume your problem is this: (q/8) + 13 = 120 If so, start by subtracting 13 from both sides of the equation. Whatever operation you do to one side of an equation you must do to the other side as well. …
  9. math

    2r+4=10 Well r=3 so that means 2xr=6 and 6+4=10. Hint: whenever a number and letter are close together you have to multply thme like 2r. The value for r is indeed 3! Another way to think about this problem is to start by subtracting …
  10. math

    2x+4(1-x)=11+5x 2x+4-4x=11+5x 6x+4=11+5x 6x=7+5x x=7 i think this is it x = 7 is not correct. Here's how the problem should work out: Use the distributive property to get rid of the parentheses and you will end up with this: 2x + 4 …

More Similar Questions