Math
posted by Kellie .
I have 2 problems I need help with both I have narrowed it down to 2 possible answers but can't decide which one is right. The first problem log subscript 5 (2x+3)=2 the choices a)13/2 and b) 14. The next problem 8^x = 16^x+2 the choices a)8 and b)8. Help please!
If log5 z = 2 then z=25
2x+3=25 x=you do it.
8^x = 16^(x+2)
8^x = 2^x+2 * 8^x+2
divide by 8^x
1=64*2^(x+2)
1/64 = 2^(x+2)
1/2^6 = 2^(x+2)
2^6 = 2^(x+2)
now take the log base 2 of each side.
Respond to this Question
Similar Questions

Precalculus
I'm studying for my precalc exam and have completed 42 practice problems. I have 3 I need to answer that I can't. Please help. What is the base of the function G(x) = log subscript b x if it's graph has points (16,4)? 
Math Exam Tuesday
My friend swears by your site so I thought I'd confirm some of my more difficult answers for my math practice exam. Is the solution set for 8^x = 16^ x+2 is it 2? 
confirm math answers
I have 3 problems I need my answers confirmed for. The solution for log subscript 3 1/9 = x is the solution 1/2? 
Math
I have 2 problems I need help with both I have narrowed it down to 2 possible answers but can't decide which one is right. The first problem log subscript 5 (2x+3)=2 the choices a)13/2 and b) 14. The next problem 8^x = 16^x+2 the choices … 
MATH
I have 2 questions the first I have narrowed down to 2 possible solutions the second has 3. What is the solution to log sub 5 (2x+3)=2 a)13/2 or b)14? 
Math
The problem 8^x = 16^x+2 the choices a)8 and b)8. Help please! Given that information I want to say the answer is 8 ? 
Algebra 2 once more
I have more answers that I would like checked. Also, there is one that I'm really confused about. I appreciate any help. :) Rewrite as the log of a single number. 1) 8 ln 2 = ln(2^8) 2) log 42  log 6 = log 36 (I think this one may … 
Math
What is the real value of x in the equation log(subscript 2)24log(subscript 2)3=log(subscript 5)x? 
physics
A particle of mass m starts from x subscript o = 0 m with V subscript o > 0 m/s. The particle experiences the variable force F subscript x = F subscript o sin (cx) as it moves to the right along the xaxis, where F subscript o and … 
physics
A particle of mass m starts from x subscript o = 0 m with V subscript o > 0 m/s. The particle experiences the variable force F subscript x = F subscript o sin (cx) as it moves to the right along the xaxis, where F subscript o and …