I don't know how to do this
How many moles of water can be made from 4 moles of oxygen gas and 16 moles of hydrogen gas? What is the limiting reagent?
Write the balanced equation.
2H2 + O2 ==> 2H2O
2 mols H2 + 1 mol O2 will produce 2 mol H2O.
So 16 mols H2 will require 8 mols O2. BUT we don't have 8 mols O2 SO O2 must be the limiting reagent.
Now, let's work from the oxygen side.
1 mol O2 requires 2 mols H2.
So 4 mols O2 will require 8 mols H2. Do we have that much? yes, we do. How much H2O will be produced. 1 mol O2 will produce how much H2O? The equations tells us 2 mols. Therefore, 4 mols O2 will produce ????H2O.
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To find out how many moles of water can be made from 4 moles of oxygen gas and 16 moles of hydrogen gas, we need to determine the limiting reagent.
From the balanced equation 2H2 + O2 → 2H2O, we can see that 2 moles of hydrogen gas react with 1 mole of oxygen gas to produce 2 moles of water.
First, let’s calculate how much hydrogen gas is required to react with the given amount of oxygen gas:
1 mole of oxygen gas requires 2 moles of hydrogen gas.
Therefore, 4 moles of oxygen gas will require 8 moles of hydrogen gas.
Since we have 16 moles of hydrogen gas, which is more than enough, hydrogen gas is in excess. Thus, the limiting reagent is oxygen gas.
Now, let’s calculate how much water can be produced:
1 mole of oxygen gas will produce 2 moles of water.
Therefore, 4 moles of oxygen gas will produce 8 moles of water.
So, from 4 moles of oxygen gas and 16 moles of hydrogen gas, we can make 8 moles of water.