A saturated solution of potassium chlorate is formed from 100 grams of water. if the saturated solution is cooled from 80 degrees celsius to 50 degrees celsius, how many grams of precipate are formed?
Do you have a table that lists the solubility at 80 and 50 degrees C?
30grams of KCL
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im sorry idk.
Subtract 50 from 80, then subtract that from 100