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determine the area of triangle abc when side ab= square root of x, side bc= square root of x, and side ca= the square root of the square root of x.


So how do I solve it. How do I add the square root of x + the square root of x + the square root of the square root of x?


what is the area actually. How would I solve for that?


1.)4(z-2)+z= -13


area in terms of the three sides of the triangle, specifically, as the square root of the product s(s – a)(s – b)(s – c) where s is the semiperimeter of the triangle, that is, s = (a + b + c)/2.

s= (3/2 sqrt x)

area = sqrt [s(s – a)(s – b)(s – c) ]
= sqrt [ (3/2 sqrt x) ( (3/2 sqrt x) – sqrtx)( (3/2 sqrt x) – sqrtx)( (3/2 sqrt x) – (3/2 sqrt x) ) ]
= sqrt ((3/2 sqrt x) (1/2 sqrt x)^3 )
= sqrt ( 3/2 * 1/8)(sqrt x)^4
= 1 x sqrt (3/16)= x/4 * sqrt 3

check that. lots of square roots to mess up.

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