Calculate the concentration of Hg2+ ions in a saturated solution of HgS(s). (Ksp=1.7×10^52)
Answer in units of mol/L
What volume of solution contains one Hg2+
ion?
Answer in units of L/ion
1x10-8
To calculate the concentration of Hg2+ ions in a saturated solution of HgS(s), we need to use the solubility product constant (Ksp) of HgS.
The balanced equation for the dissolution of HgS(s) is:
HgS(s) ⇌ Hg2+(aq) + S2-(aq)
From the equation, we can see that one mole of HgS produces one mole of Hg2+ ions.
To find the concentration of Hg2+ ions, we can use the equation:
Ksp = [Hg2+][S2-]
Given that Ksp = 1.7×10^52, we assume that the solubility of HgS is x moles per liter. Therefore, the molar concentration of Hg2+ ions is also x mol/L.
Substituting these values into the equation, we get:
1.7×10^52 = x * x
Taking the square root of both sides:
x = √(1.7×10^52)
x ≈ 1.3×10^26 mol/L
Therefore, the concentration of Hg2+ ions in a saturated solution of HgS(s) is approximately 1.3×10^26 mol/L.
Now, let's calculate the volume of solution that contains one Hg2+ ion.
Since the concentration of Hg2+ ions is x = 1.3×10^26 mol/L, we can use the equation:
Volume = 1 / [Hg2+]
Substituting the value, we have:
Volume = 1 / (1.3×10^26 mol/L)
Volume ≈ 7.7×10^-27 L/ion
Therefore, the volume of solution that contains one Hg2+ ion is approximately 7.7×10^-27 L/ion.
To calculate the concentration of Hg2+ ions in a saturated solution of HgS(s), we need to use the solubility product constant (Ksp) for HgS.
The solubility product constant (Ksp) expression for HgS(s) can be written as follows:
HgS ⇌ Hg2+ + S2-
The Ksp value provided (Ksp = 1.7×10^52) indicates the equilibrium constant for this reaction. Since the stoichiometric ratio between HgS and Hg2+ ions is 1:1, the concentration of Hg2+ ions in the saturated solution will be equal to the solubility of HgS.
To find the concentration, we need to take the square root of the Ksp value:
[Hg2+] = √(Ksp)
[Hg2+] = √(1.7×10^52)
Calculating this on a calculator, we find that the concentration of Hg2+ ions is approximately 1.3×10^26 mol/L.
Now, let's move on to the second part of the question, which asks for the volume of solution containing one Hg2+ ion.
To determine the volume of solution containing one Hg2+ ion, we need to rearrange the concentration formula to solve for volume:
Volume = 1 / [Hg2+]
Volume = 1 / (1.3×10^26)
Evaluating this expression, we find that the volume of solution containing one Hg2+ ion is approximately 7.7×10^(-27) L/ion.
Therefore, the concentration of Hg2+ ions is approximately 1.3×10^26 mol/L, and the volume of solution containing one Hg2+ ion is approximately 7.7×10^(-27) L/ion.