physics

A spiral spring of natural length of 30.0cm and a constant force of 20N/m is compressed to 20cm. Calculate the energy stored in the spring.

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  1. 30 cm - 20 cm = 10 cm = .1 meter

    F = k x
    20 = k (.1)
    so
    k = 200

    E = (1/2) k x^2
    = (1/2)(200)(.01)
    = 1 Joule

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    posted by Damon

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