# physics

The air in the syringe is at a pressure of 2.0×105Pa. The piston is slowly moved into the
syringe, keeping the temperature constant, until the volume of the air is reduced from
80 cm3 to 25 cm3. Calculate the final pressure of the air.

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1. P V = n R T

n R and T do not change so

P1 V1 = P2 V2

2 *10^5 * 80 = P2 * 25
so
P2 = 2*10^5 * (80/25)

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posted by Damon

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