physics

a body of mass 25kg moving at 3m/s on a rough horizontal floor is brought to rest after sliding through a distance of 2.5m on the floor. calculate the coefficient of sliding friction.

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  1. t is time to stop

    a = 3/t

    d = (1/2)a t^2
    2.5 = .5 (3/t) t^2
    2.5 = 1.5 t
    t = 1.67 seconds to stop
    then
    a = 3/t = 1.8 m/s^2
    F = ma
    F = 25 * 1.8 = 45 Newtons
    weight = 25g = 245 Newtons

    coef of friction = F/weight = 45/245
    = .184

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    posted by Damon
  2. Thank you so much for helping me solve this problem

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  3. not correct

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    posted by favour
  4. f/mg =45\25*10=45/250=0.18

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    posted by favour
  5. not f\weight

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    posted by favour

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