# physics

a body of mass 25kg moving at 3m/s on a rough horizontal floor is brought to rest after sliding through a distance of 2.5m on the floor. calculate the coefficient of sliding friction.

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1. t is time to stop

a = 3/t

d = (1/2)a t^2
2.5 = .5 (3/t) t^2
2.5 = 1.5 t
t = 1.67 seconds to stop
then
a = 3/t = 1.8 m/s^2
F = ma
F = 25 * 1.8 = 45 Newtons
weight = 25g = 245 Newtons

coef of friction = F/weight = 45/245
= .184

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posted by Damon
2. Thank you so much for helping me solve this problem

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3. not correct

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posted by favour
4. f/mg =45\25*10=45/250=0.18

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posted by favour
5. not f\weight

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posted by favour

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