Math help :(

I don't get any of these practice problems.

5. 2(x – 3) = 2x

one solution
no solutions
infinitely many solutions

6. 3(y – 3) = 2y – 9 + y

one solution
no solutions
infinitely many solutions


7. 10x – 2 – 6x = 3x – 2 + x

one solution
no solutions
infinitely many solutions


8. 4(x + 3) + 2x = x – 8

one solution
no solutions
infinitely many solutions

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  1. http://openstudy.com/updates/52a1e689e4b088e695c0cc86

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    posted by Damon
  2. 2(x-3) = 2x
    2x - 6 = 2x
    Move 2x to the left side and change sign. Then put zero after the equal sign.

    2x - 2x - 6 = 0

    2x's cancels out.
    0 = 6

    No Solution
    ________________________________

    3(y - 3)= 2y - 9 + y
    3y - 9 = 3y - 9
    Move 3y to the left and -9 to the right and change their signs.
    3y - 3y = - 9 + 9
    0 = 0

    All real numbers > many solutions
    ____________________________________

    10x - 2 - 6x = 3x - 2 + x
    4x - 2 = 4x - 2
    Same as problem 6
    ___________________________________

    4(x + 3)+ 2x = x - 8
    4x + 12 + 2x = x - 8
    6x + 12 = x - 8
    Move x to the left and 12 to the right, then change their signs.

    6x - x = -20
    5x = -20
    x = -4 > one solution

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    posted by Chelle
  3. Decide whether each equation has one solution, no solutions, or infinitely many solutions.
    1. 2(x - 3) = 2x
    A. one solution B. no solutions C. infinitely many solutions
    2. 3(y - 3) = 2y - 9 + y
    A. one solution B. no solutions C. infinitely many solutions
    3. 10x - 2 - 6x = 3x - 2 + x
    A. one solution B. no solutions C. infinitely many solutions 4. 4(x + 3) + 2x = x - 8 A. one solution B. no solutions C. infinitely many solutions

    1. 2(x - 3) = 2x -- distribute through the parenthesis 2x - 6 = 2x -- add 6 to both sides 2x = 2x + 6 -- subtract 2x from both sides
    2x - 2x = 6 0 = 6 (incorrect)
    If you answer comes out not equal, then there is no solution

    2. 3(y - 3) = 2y - 9 + y -- distribute and combine 3y - 9 = 3y - 9 -- subtract 3y 3y - 3y - 9 = - 9 -- add 9 3y - 3y = -9 + 9 0 = 0 (correct)

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    posted by Damon
  4. If you answer comes out equal, then there is infinite solutions
    3. 10x - 2 - 6x = 3x - 2 + x -- combine like terms 4x - 2 = 4x - 2 same thing here...it is gonna come out to 0 = 0 making it have infinite solutions
    4. 4(x + 3) + 2x = x - 8 4x + 12 + 2x = x - 8 6x + 12 = x - 8 6x - x = -8 - 12 5x = - 20
    x = -4
    ONE SOLUTION

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    posted by Damon
  5. ze furtse fart that is correct by yht way...

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