# algebra 2 honors

2x^2-12x+32=x^2 how would I solve this by factoring?

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1. 2x^2-12x+32=x^2
x^2 - 12x + 32 = 0
(x-8)(x-4) = 0
x = 8 or x = 4

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posted by Reiny
2. 2x^2 - 12x + 32 = x^2

Move x^2 to the left side and change sign then put zero after equal sign..

2x^2 - x^2 - 12x + 32 = 0
x^2 - 12x + 32 = 0

(x - 4)(x - 8) = 0

x - 4 = 0 x - 8 = 0
x - 4 + 4 = 0 + 4 x - 8 + 8 = 0 + 8
x = 4 x = 8

x = 4,8

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posted by Chelle

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