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Physics (2)
If it takes 4.00 J of work to stretch a Hooke's Law spring 10.0 cm from its unstressed length, determine the extra work required to stretch it an additional 10.0 cm
asked by Whitney on October 13, 2011 
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If it takes 4.12 J of work to stretch a Hooke's law spring 12.1 cm from its unstressed length, determine the extra work required to stretch it an additional 10.0 cm.
asked by Luke on September 29, 2009 
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It takes 3.38 J of work to stretch a Hooke’slaw spring 5.63 cm from its unstressed length. How much the extra work is required to stretch it an additional 4.22 cm? Answer in units of J
asked by jason on November 16, 2012 
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The force required to stretch a Hooke’slaw spring varies from 0 N to 70.4 N as we stretch the spring by moving one end 5.35 cm from its unstressed position. Find the force constant of the spring. Answer in units of N/m
asked by Patrick on December 14, 2012 
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The force required to stretch a Hooke’slaw spring varies from 0 N to 63.5 N as we stretch the spring by moving one end 5.31 cm from its unstressed position. Find the force constant of the spring. Answer in units of N/m
asked by Ted on February 8, 2013 
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A force of 250 N is required to stretch a spring 5m from rest. Using Hooke's law, F=kx, how much work, in joules, is required to stretch the spring 7m from rest? The energy required scales with x^2. Multiply 250 J by (7/5)^2.
asked by Mischa on April 23, 2007 
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The force required to stretch a Hooke’slaw spring varies from 0 N to 68.1 N as we stretch the spring by moving one end 16.2 cm from its unstressed position. Find the work done in stretching the spring
asked by james on December 20, 2012 
Math Problem (please help)
Use Hooke's Law for springs, which states that the distance a spring is stretched (or compressed) varies directly as the force on the spring. A force of 265 newtons stretches a spring 0.15 meter (see figure). (a) How far will a
asked by Ada on September 10, 2014 
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Use Hooke's Law for springs, which states that the distance a spring is stretched (or compressed) varies directly as the force on the spring. A force of 265 newtons stretches a spring 0.15 meter (see figure). (a) How far will a
asked by Ada on September 10, 2014 
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Sir Robert Hooke (16351703), studied the elastic properties of springs and formulated the law that bears his name. Hooke found the relationship among the force a spring exerts, F, the distance from equilibrium the end of the
asked by Anonymous on February 20, 2011