Algebra

How do I use an x and y-intercept to write an equation in standard form? For example, how do I use the x-intercept of 3 and y-intercept of 6 to write an equation in standard form?

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  1. The x-intercept of 3 is really the point (3,0) and
    the y-intercept of 6 is really the point (0,6)

    So you are just given two points,
    find the slope, then find the equation of the line in your usual way.

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    posted by Reiny
  2. Okay, but how can I (if I can) write an equation in standard form (ax + by = c) using the two intercepts?

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  3. Ahh, you mean directly?

    x/3 + y/6 = 1

    (in general: x/(x-intercept) + y/(y-intercept) = 1 )

    once you have that, multiply each term by 6, the LCD
    2x + y = 6

    check if both points lie on it.
    for (3,0)
    2(3) + 0 = 6 , ok
    for (0,6)
    0 + 6 = 6 , ok

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    posted by Reiny
  4. Thank you so much! It is surprising that my school didn't show us that method.

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