# Physics

A train traveling at a speed of 110km/h uniformly decelerates for 20 seconds. During that time it travels 450m

a) what is the acceleration m/s square?

b) what is its speed after the deceleration? (km/h)

Could really use some help. Thank you.

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1. s = 110t + 1/2 at^2, so
110(20)-(1/2)a(20^2) = 450
a = -8.75

Now, you can get v = 110+at

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posted by Steve

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