# math Steve for your help

3.2g of a mixture of kn03 and nan03 was heated to constant weight which was found to be 2.64g. What is the % kn03 in mixture

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3. 👁 150
1. If I get time I will look at this, but really you need a chemistry teacher.

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2. 2KNO3 ==> 2KNO2 + O2 and
2NaNO3 ==> 2NaNO2 + O2

Let X = mass KNO3
and Y = mass NaNO3
---------------------
eqn 1 is X + Y = 3.2
eqn 2 is
X(molar mass KNO2/KNO3) + Y(molar mass NaNO2/NaNO3) = 2.64

Solve the two equations simultaneously to find X, then
%X = (mass X/3.2)*100 = ?

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