Math 9

Find the real number a for which the lines −4x+ 3y = 7 and ax− 2y = 4 will be perpendicular.

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  1. 3 y = 4 x + 7
    y = (4/3) x + 7/3
    slope is (4/3)
    slope of perpendicular = -3/4

    so now look at second line, has to have m = slope = -3/4

    2 y = a x - 4
    y = (a/2) x - 2
    so
    -3/4 = a/2
    a = -3/2

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  2. This Question is very hard. I like for my son.

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