Physics

An electron is released between two metal plates 40.0mm apart experiences an acceleration of 1x10^12m/s^2. Determine the potential difference across the plates.

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  1. F=ma
    E=F/e=ma/e
    E=Δφ/Δx =>
    Δφ =E Δx= ma Δx /e=
    =9.1•10⁻³¹•10¹²•0.04/1.6•10⁻¹⁹=0.2275 V

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