The mass of an individual atom of calcium is 40.08 amu. How many atoms would weigh a total of 15.46 g of this element if the mass of 1 amu is 1.6605x10-24 g?

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  1. 40.08 amu/atom x 1.6605E-24g/amu x # atoms = 15.46g.
    Solve for # atoms.

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