3x-2y=8
2x=2y=22
How i solve with substitution?
Please correct your typo.
how do i solve with substitution?
3x-2y=8
2x=2y=22
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I assume you mean
3x-2y=8
2x-2y=22 ?????
if so then get y = some function of x from the second equation
2 x - 2 y = 22
is
x - y = 11
or
y = (x - 11)
substitute that in the first equation
3 x - 2 (x - 11) = 8
3 x - 2 x + 22 = 8
x = - 14
then go back for y
y - -14 - 11 = -25
If I guessed wrong on your typo, then I told you how to do it anyway.
Since the + and = signs are on the same key, I suspect you meant
3x-2y = 8
2x+2y = 22 ---->x+y=11 --->y = 11-x
sub into the 1st
3x - 2(11-x) = 8
3x - 22+2x = 8
5x = 30
x = 6
then y = 11-6 = 5
Good mind reading :)
To solve the given system of equations using the substitution method, we need to isolate one variable in one equation and substitute it into the other equation.
Let's solve the first equation, 3x - 2y = 8, for x:
3x = 8 + 2y
x = (8 + 2y)/3
Now we will substitute this expression for x into the second equation, 2x + 2y = 22:
2((8 + 2y)/3) + 2y = 22
Simplify the equation by multiplying through by 3 to eliminate the fraction:
2(8 + 2y) + 6y = 66
16 + 4y + 6y = 66
10y + 16 = 66
Subtract 16 from both sides of the equation:
10y = 66 - 16
10y = 50
Divide both sides by 10:
y = 50/10
y = 5
Now substitute the value of y back into the first equation to find x:
3x - 2(5) = 8
3x - 10 = 8
3x = 8 + 10
3x = 18
Divide both sides by 3:
x = 18/3
x = 6
Therefore, the solution to the system of equations is x = 6 and y = 5.