# Physics

A 13g bullet traveling 330 m/s penetrates a 2.0 kg Block of wood and emerges going 270 m/s . If the block is stationary on a frictionless surface when hit how fast does it move after the bullet emerges?

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1. momentum before = momentum after

momentum before = .013 * 330

momentum after = .013 * 270 + 2 v

so

2 v = .013 (330 - 270)

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2. thank you

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3. 590.15

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