Sugar comes in 2 pound bags and flour comes in 5 lb bags. Thomas bought 3 more bag of sugar than flour and the total weight was 48 pounds. How many bags of sugar and flour did Thomas buy?
if there are x bags of flour, then
2(x+3) + 5x = 48
Thanks so much!!
Ok, now this is a question I was looking for.
So, I have the answer choices, so I know what to do.
A) 9 bags of sugar and 10 bags of flour.
Sugar is 2 pounds. So 9X2= 18
Flour is 5 pounds, which is 10X5=50
50+18=68 That is not 48 pounds. Moving on.
B) 4 bags of sugar and 8 bags of flour.
We know the drill, so let's go!
4X2=8
8X5=40
40+8=48
Yay! B is correct. There is your answer. Hope this helped!
To solve this problem, let's use algebraic equations. Let's assign variables to represent the unknowns. Let 'S' represent the number of bags of sugar Thomas bought, and let 'F' represent the number of bags of flour he bought.
From the given information, we can form two equations:
1) Sugar comes in 2-pound bags, so the weight of sugar purchased is 2S.
2) Flour comes in 5-pound bags, so the weight of flour purchased is 5F.
According to the problem, Thomas bought 3 more bags of sugar than flour, so we can write another equation:
3) S = F + 3
The total weight purchased is 48 pounds, which is the sum of the weights of sugar and flour. So we can write one more equation:
4) 2S + 5F = 48
Now we have a system of equations. We can substitute the value of S from equation 3 into equation 4 and solve for F:
2(F + 3) + 5F = 48
2F + 6 + 5F = 48
7F + 6 = 48
7F = 42
F = 42/7
F = 6
By substituting the value of F back into equation 3, we can find the value of S:
S = 6 + 3
S = 9
Hence, Thomas bought 9 bags of sugar and 6 bags of flour.