Coefficient of volume expansion of some liquids(a/˚C)
Alcohol=1.1x〖10〗^(-4)
Glycerin=5.0x〖10〗^(-4)
Water=3.7x〖10〗^(-4)
Ether=1.63x〖10〗^(-4)
Mercury= 1.1x〖10〗^(-4
What is the increase in volume of 0.3m cube of ethyl alcohol when heated from 15˚C to 20˚C?
Increase = a(T-To)Vo =
1.63*10^-4(20-15)0.3=2.45*10^-4 m^3.
To calculate the increase in volume of ethyl alcohol when heated, we can use the formula:
ΔV = V₀ * β * ΔT
Where:
ΔV is the change in volume
V₀ is the initial volume
β is the coefficient of volume expansion of the liquid
ΔT is the change in temperature in ˚C
Given:
V₀ = 0.3 m³ (initial volume)
β = 1.1 x 10^(-4) ˚C⁻¹ (coefficient of volume expansion of ethyl alcohol)
ΔT = (20˚C - 15˚C) = 5 ˚C (change in temperature)
Now, we can substitute these values into the formula to calculate the change in volume:
ΔV = 0.3 m³ * (1.1 x 10^(-4) ˚C⁻¹) * 5 ˚C
Simplifying the equation:
ΔV = 0.3 m³ * (1.1 x 10^(-4) * 5) ˚C
ΔV = 0.3 m³ * (5.5 x 10^(-4)) ˚C
ΔV = 1.65 x 10^(-4) m³
Therefore, the increase in volume of 0.3 m³ of ethyl alcohol when heated from 15˚C to 20˚C is approximately 1.65 x 10^(-4) m³.