I have an assignment to write an equation to point-slope form, then to standard form, and then to slope-intercept form. I have used the points (-2,-1) or (1,2), but I used (-2,-1).
Now, I have the point-slope form of y + 1= 1(x + 2) and the standard form of y – 1x = -1. When I convert into slope-intercept form, I am getting the slope as -1, which is the problem. Could someone please tell me where I am going wrong?
in standard form we usually lead with the x term with a positive coefficient, so I wanted a +x as my first term, it was -x .
to change a standard form to slope- yintercept form usually takes 2 steps:
1. move all terms except the y term to the right
4x - 5y = 8 ---≥ -5y = -4x + 8
2. divide each term by the coefficient of the y term
-5y = -4x + 8 ----> y = (-4/-5)x + 8/-5
y = (4/5)x - 8/5 , just an example, has nothing to do with your question
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