Chemistry

What is the osmotic pressure of a 50% sucrose solution at a temperature of 37 degrees celcius with a molar mass of sucrose of 342.30 grams

  1. 7
asked by Ruffles
  1. *repost*

    Formula for osmotic pressure:
    Π = MRT * i
    where
    m = molarity (mol solute / L solution)
    R = universal gas constant = 0.0821 L-atm/mol-K
    T = temperature (K)
    i = van't Hoff factor (approximately equal to ionizable ions)

    Note that sucrose is soluble in water, but does not form ions in water, thus i = 1.
    I am not sure what that 50% sucrose solution means, so I assumed it's by mass, or 50 g sucrose over 100 g solution. Assuming density of solution is equal to that of water (which is 1 g/mL),
    Π = MRT
    Π = [(50/342)/((100/1)/1000)] * 0.0821 * (37 + 273)
    Π = 37.21 atm

    hope this helps :3

    posted by Jai

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