# Physics

Neutrons have a rest mass of 1.6749*10-27 kg (equivalent to 939.6 MeV).

If a certain neutron has a total energy of 949 MeV, what are its relativistic mass energy in MeV, its speed in m/s, its kinetic energy in MeV, and its momentum in kg.m.s-1?

1. m₀=1.6749•10⁻²⁷kg
E=949 MeV=1.52•10⁻¹⁰ J
E=mc² =
m=E/c² =1.52•10⁻¹⁰/(3•10⁸)²=1.6889•10⁻²⁷kg

m=m₀/√(1- β²)
(1- β²)=(m₀/m)²= (1.6749•10⁻²⁷/1.6889•10⁻²⁷)²=0.983
β =sqrt(1-0.983)=0.128
v= β•c=0.128•3•10⁸=3.85•10⁷m/s
m₀c²=1.6749•10⁻²⁷•(3•10⁸)²=1.5074•10⁻¹⁰ J =940.8 MeV
KE=mc²- m₀c²= 949-940.8 =8.2 Mev
p=m₀ βc /√(1- β²)= ….

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