Physics
Neutrons have a rest mass of 1.6749*1027 kg (equivalent to 939.6 MeV).
If a certain neutron has a total energy of 949 MeV, what are its relativistic mass energy in MeV, its speed in m/s, its kinetic energy in MeV, and its momentum in kg.m.s1?
asked by
Jane

m₀=1.6749•10⁻²⁷kg
E=949 MeV=1.52•10⁻¹⁰ J
E=mc² =
m=E/c² =1.52•10⁻¹⁰/(3•10⁸)²=1.6889•10⁻²⁷kg
m=m₀/√(1 β²)
(1 β²)=(m₀/m)²= (1.6749•10⁻²⁷/1.6889•10⁻²⁷)²=0.983
β =sqrt(10.983)=0.128
v= β•c=0.128•3•10⁸=3.85•10⁷m/s
m₀c²=1.6749•10⁻²⁷•(3•10⁸)²=1.5074•10⁻¹⁰ J =940.8 MeV
KE=mc² m₀c²= 949940.8 =8.2 Mev
p=m₀ βc /√(1 β²)= ….
posted by Elena

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posted by Ben
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