if the man in figure 6.13 pulls 1 m of rope downward with a force of 100N, and the load rises 1/7 as high (about 14 cm) what is the maximum load that can be lifted?
To solve this problem, we can use the concept of mechanical advantage. Mechanical advantage is a measure of how much a machine can multiply the input force applied to it.
In this case, we have a situation where the load rises 1/7 as high as the distance the man pulls the rope downward. This means the mechanical advantage is 1/7.
To find the maximum load that can be lifted, we need to determine the force required to lift it. We know that the man pulls the rope downward with a force of 100N.
So, to calculate the maximum load, we can use the formula:
Maximum Load = Input Force / Mechanical Advantage
In this case, the input force is 100N and the mechanical advantage is 1/7. Let's substitute these values into the formula:
Maximum Load = 100N / (1/7)
To divide by a fraction, we can multiply by its reciprocal. So, let's multiply 100N by the reciprocal of 1/7, which is 7/1:
Maximum Load = 100N * (7/1)
Maximum Load = 700N
Therefore, the maximum load that can be lifted in this scenario is 700 Newtons.