A 1-L flask is filled with 1.25g of argon at 25 ∘C. A sample of ethane vapor is added to the same flask until the total pressure is 1.35atm .
What is the partial pressure of argon, PAr, in the flask?
What is the partial pressure of ethane, Pethane, in the flask?
Use PV = nRT and solve for pAr. n = grams Ar/atomic mass Ar.
Then Ptotal = 1.35 atm = pAr + pethaneposted by DrBob222