Chemistry

A reaction: A(aq) + B(aq) <-> C(aq)

has a standard free-energy change of –4.65 kJ/mol at 25 °C.

What are the concentrations of A, B, and C at equilibrium if, at the beginning of the reaction, their concentrations are 0.30 M, 0.40 M, and 0 M, respectively?

Im not even sure where to start. Can you walk me through this please?

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  1. I can show you how.
    dG = -RT*lnK
    dG = -4.65 kJ/mol = 4650 J/mol
    substitute in the above and solve for K. Then
    ............A + B ==> C
    I..........0.3..0.4...0
    C..........-x...-x....x
    E........0.3-x...4-x..x
    Substitute the E line into the Keq expression (use K from the first calculation with delta G) and solve for x. Then x, 0.3-x and 0.4-x will give you the equilibrium concns.

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