Algebra 1

Write an equation in standard form of the line that passes through the given points.
Can someone check my answers?

(2,6)(3,8) -2x+y=2
(7,-3)(4,-1) 4/3x+y=19/3
(3,-8)(5,-9) 1/2x+y=-13/2
(-5,6)(2,-3) 9/7x+y=-3/7
(-3,-1)(6,-8) 7/9x+y=-10/3

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  1. better form ....
    -2x + y = 2 ---> 2x - y = -2
    4/3x+y=19/3 ----> 4x + 3y = 19
    1/2x+y=-13/2 ----> x + 2y = -13
    9/7x+y=-3/7 ---->9x + 7y = -3
    7/9x+y=-10/3 ----> 7x + 9y =-30

    can you see what I did?
    A proper way to write equation in standard form:
    - no fractions should show up (You can always get rid of fractions by multiplying each term by the LCD)
    - the x term should be first and be positive

    Now to check if they are right, simply sub in your points, both must satisfy your equation.

    I think the second one is wrong!
    slope = (-1+3)/(4-7) = - 2/3
    using (4,-1)
    y+1 = (-2/3)(x-4)
    3y + 3 = -2x + 8
    2x + 3y = 5
    ........ both points work in this one

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    posted by Reiny
  2. -2x + y = 2

    2x + 3y = 5

    x + 2y = -13

    9x +7y = -3

    7x + 9y = -30

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    posted by Kuai
  3. thanks

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    posted by Jynessa

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