A plane flies due north (90° from east) with a velocity of 100 km/h for 3 hours. During this time, a steady wind blows southeast at 30 km/h at an angle of 315° from due east. After 3 hours, where will the plane’s position be relative to its starting point? Show your work.

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  1. v=sqrt{v(p)²+v(w)²-2v(p)v(w)cos α}=
    =sqrt{100²+30²-2•100•30cos45} =81.6 km/h
    s= vt=81.6•3=244.8 km
    β= 85°v (northeast)

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