Glucose can be classified as an aldohexose. Name the following monosaccharide to indicate its carbonyl group and the number of carbon atoms.
HO-CH2-C(=o)-c(H2O)-C(H2O)-CH2-OH
The given monosaccharide can be named as 2-deoxy-D-ribose. The carbonyl group in this monosaccharide is a ketone group, indicated by the "C(=O)" portion in the structure. Additionally, since this monosaccharide has 6 carbon atoms, it is classified as an aldohexose.
To name the given monosaccharide and indicate its carbonyl group and the number of carbon atoms, we can break down the structure and analyze it step by step.
The structure you provided, HO-CH2-C(=O)-C(H2O)-C(H2O)-CH2-OH, represents a hexose sugar, meaning it contains six carbon atoms. Now let's identify the carbonyl group.
The carbonyl group in this monosaccharide is represented by the C(=O) in the structure. Looking at the structure, we see that the carbonyl group is located between the second and third carbon atoms. Since it is an aldehyde group (CHO), we can classify this monosaccharide as an aldohexose.
Now, to name the monosaccharide, we can use the IUPAC nomenclature. Starting from the leftmost carbon and numbering each carbon atom, we get:
1 - C(=O)
2 - CH2OH
3 - CH(OH)
4 - CH(OH)
5 - CH2OH
6 - CH2OH
Based on these numbering, we can name the given monosaccharide as D-glucohexose. The prefix "D-" represents the configuration of the hydroxyl group on the highest numbered chiral carbon, which, in this case, is on the right side.
So, the monosaccharide HO-CH2-C(=O)-C(H2O)-C(H2O)-CH2-OH can be named as D-glucohexose, indicating its carbonyl group as an aldehyde (aldohexose) and the presence of six carbon atoms in the structure.