Calculus

Solve the separable differential equation 10x−6ysqrt(x^2+1)dy/dx=0. with the initial condition y(0)=4.

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asked by Robin
  1. 10x−6y√(x^2+1)dy/dx=0
    6y√(x^2+1) dy/dx = 10x
    6y dy = 10x/√(x^2+1) dx
    3y^2 = 10√(x^2+1) + c

    Since y(0) = 4,
    3*16 = 10+c
    c = 38

    now you have it.

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    posted by Steve

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