Mr. Thomas spent 1600.00 of his savings on a TV and 2/5 of the remainder on a refrigerator. He had 1/3 of his original amount of savings left. What was Mr. Thomas's original savings?
wow this was very confusing
Did not help at ALLLLLLL
To solve this problem, we can work backwards. Let's assume the original amount of savings is "x."
1. Mr. Thomas spent $1600 on a TV, so the remainder of his savings is x - $1600.
2. He then spent 2/5 of the remainder on a refrigerator, which is (2/5)*(x - $1600).
3. After buying the refrigerator, he had 1/3 of his original amount of savings left, so the remaining amount is 1/3 * x.
Now we can create an equation and solve for x:
x - $1600 - (2/5)*(x - $1600) = 1/3 * x
To simplify, let's first distribute (2/5) through (x - $1600):
x - $1600 - (2/5)*x + (2/5)*$1600 = 1/3 * x
Now, let's combine like terms:
x - $1600 - (2/5)*x + (2/5)*$1600 = 1/3 * x
x - $1600 - (2/5)*x + $640 = 1/3 * x
Now, let's isolate the x term:
x - (2/5)*x - 1/3 * x = $1600 - $640
To do this, we'll need a common denominator, which is 15:
15x/15 - (6/15)*x - 5/15 * x = $960
Combining like terms:
(15x - 6x - 5x)/15 = $960
(4x)/15 = $960
To solve for x, multiply both sides by 15:
4x = $960 * 15
4x = $14400
Dividing both sides by 4:
x = $14400 / 4
x = $3600
Therefore, Mr. Thomas's original savings was $3600.
s - 1600 - 2/5 (s-1600) = s/3
s = 3600
check:
he spent 1600 leaving 2000
he spent 800 leaving 1200
1200 = 3600/3