Suppose that 20% of Canadians smoke. In a random sample of 20 Canadians, find the probability that more than 1 smokes
(P more than 1 ) = 1- P(X = 0 )
1- binompdf(20, .2, 0) = .9885
or 1- (20C0)(.2)^0(.8)^20
= 1-.0115= .9885
1- binompdf(20, .2, 0) = .9885
or 1- (20C0)(.2)^0(.8)^20
= 1-.0115= .9885