# Jr Applied Math (Algebra II)

A landscaping company placed two orders with a nursery. The first order was for 13 bushes and 4 trees, and totaled \$487.00. The second was for 6 bushes and 2 trees, and totaled \$232.00. The bills do not list the per-item price. What were the costs of one bush and of one tree?

1. Looks like algebra I to me. Anyway,

(1) 13b+4t = 487
(2) 6b+2t = 232
Subtracting twice #2 from #1 we get
b = 23
so, t = 47

b+t = 70

posted by Steve
2. c=15+10h
c=8h

posted by isaiah
3. c=15+10h
c=8h

posted by Anonymous

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