These problems I really don't understand and really need serious help :)
1.What the product of (5.1 x 10^3)x
(3.2 x 10^3)?(Please express your answer in scientific notation)
16.32 x 10^6
1.632 x 10^7
16.32 x 10^9
1.632 x 10^10
2.What is the product of (7.28 x 10^-2)x(9.1 x 10^-2)? (Please express your answer in scientific notation)
6.6248 x 10^-3
66.248 x 10^-4
6.6248 x 10^4
66.248 x 10^-3
3.What is the quotient of (2.965 x 10^7)
:(5x10^3)? :=divide
14.825 x 10^4
5.93 x 10^5
14.825 10^5
5.93 10^3
4.Find the product.(4.0 x 10^-2)x
(5.2 x 10^8)
20.8 x 10^8
2.08 x 10^7
2.08 x 10^6
20.8 x 10^7
Online, “*” is used to indicate multiplication to avoid confusion with “x” as an unknown.
Multiply the base values and add the exponents.
(5.1*10^3) * (3.2*10^3) = 16.32*10^6
Use the same process for the remaining problems.
Sure! Let's solve these problems step by step:
1. To find the product of (5.1 x 10^3) and (3.2 x 10^3), we multiply the numerical parts and add the exponents.
Step 1: Multiply the numerical parts: 5.1 x 3.2 = 16.32
Step 2: Add the exponents: 10^3 x 10^3 = 10^(3+3) = 10^6
So, the product in scientific notation is: 16.32 x 10^6
2. To find the product of (7.28 x 10^-2) and (9.1 x 10^-2), we follow the same process as before.
Step 1: Multiply the numerical parts: 7.28 x 9.1 = 66.248
Step 2: Add the exponents: 10^-2 x 10^-2 = 10^(-2+(-2)) = 10^(-4)
So, the product in scientific notation is: 66.248 x 10^-4
3. To find the quotient of (2.965 x 10^7) divided by (5 x 10^3), we divide the numerical parts and subtract the exponents.
Step 1: Divide the numerical parts: 2.965 ÷ 5 = 0.593
Step 2: Subtract the exponents: 10^7 ÷ 10^3 = 10^(7-3) = 10^4
So, the quotient in scientific notation is: 0.593 x 10^4
4. To find the product of (4.0 x 10^-2) and (5.2 x 10^8), we follow the same process as before.
Step 1: Multiply the numerical parts: 4.0 x 5.2 = 20.8
Step 2: Add the exponents: 10^-2 x 10^8 = 10^(-2+8) = 10^6
So, the product in scientific notation is: 20.8 x 10^6
I hope this helps you understand these problems better! Let me know if you have any more questions.