These problems I really don't understand and really need serious help :)
1.What the product of (5.1 x 10^3)x
(3.2 x 10^3)?(Please express your answer in scientific notation)
16.32 x 10^6
1.632 x 10^7
16.32 x 10^9
1.632 x 10^10
2.What is the product of (7.28 x 10^-2)x(9.1 x 10^-2)? (Please express your answer in scientific notation)
6.6248 x 10^-3
66.248 x 10^-4
6.6248 x 10^4
66.248 x 10^-3
3.What is the quotient of (2.965 x 10^7)
:(5x10^3)? :=divide
14.825 x 10^4
5.93 x 10^5
14.825 10^5
5.93 10^3
4.Find the product.(4.0 x 10^-2)x
(5.2 x 10^8)
20.8 x 10^8
2.08 x 10^7
2.08 x 10^6
20.8 x 10^7
scientific notation has the form
a 10^n, where "a" is a numer between 1 ≤ a ≤ 9
and n is an integer
I will do one of them for you, then you follow that method for the others
2. (7.28 x 10^-2)x(9.1 x 10^-2)
= (7.28 x 9.1) x (10^-2 x 10^-2)
= 66.248 x 10^-4
but I have to change the 66.248 to 6.248
So I move the decimal to the left, making my number smaller
BUT, that would change the value, so to compensate I make the 10^-4 larger by that same factor , 10^-4 ----> 10^-3
= 6.6248 x 10^-3
1. To find the product of (5.1 x 10^3) and (3.2 x 10^3), you multiply the coefficients (5.1 x 3.2) and add the exponents of the powers of 10 (10^3 x 10^3).
5.1 x 3.2 = 16.32
10^3 x 10^3 = 10^(3+3) = 10^6
So, the product is 16.32 x 10^6.
Answer: 16.32 x 10^6
2. To find the product of (7.28 x 10^-2) and (9.1 x 10^-2), you multiply the coefficients (7.28 x 9.1) and add the exponents of the powers of 10 (-2 + -2).
7.28 x 9.1 = 66.248
10^-2 + 10^-2 = 10^(-2-2) = 10^-4
So, the product is 66.248 x 10^-4.
Answer: 66.248 x 10^-4
3. To find the quotient of (2.965 x 10^7) divided by (5 x 10^3), you divide the coefficients (2.965 ÷ 5) and subtract the exponents of the powers of 10 (10^7 - 10^3).
2.965 ÷ 5 = 0.593
10^7 - 10^3 = 10^(7-3) = 10^4
So, the quotient is 0.593 x 10^4.
Answer: 5.93 x 10^5
4. To find the product of (4.0 x 10^-2) and (5.2 x 10^8), you multiply the coefficients (4.0 x 5.2) and add the exponents of the powers of 10 (-2 + 8).
4.0 x 5.2 = 20.8
10^-2 + 10^8 = 10^(8-2) = 10^6
So, the product is 20.8 x 10^8.
Answer: 20.8 x 10^8
1. To find the product of two numbers in scientific notation, you need to multiply the coefficients and add the exponents.
For the first problem, the coefficients are 5.1 and 3.2, and the exponents are 10^3.
To get the product of the coefficients, multiply 5.1 by 3.2:
5.1 x 3.2 = 16.32
To get the product of the exponents, add 10^3 to 10^3:
10^3 + 10^3 = 10^6
Therefore, the product in scientific notation is 16.32 x 10^6.
2. Similar to problem 1, to find the product of two numbers in scientific notation, you need to multiply the coefficients and add the exponents.
For the second problem, the coefficients are 7.28 and 9.1, and the exponents are 10^-2.
Multiply the coefficients:
7.28 x 9.1 = 66.248
Add the exponents:
-2 + -2 = -4
Therefore, the product in scientific notation is 66.248 x 10^-4.
3. To find the quotient of two numbers in scientific notation, you need to divide the coefficients and subtract the exponents.
For the third problem, the coefficient is 2.965 and the exponent is 10^7, and the coefficient is 5 and the exponent is 10^3.
Divide the coefficients:
2.965 ÷ 5 = 0.593
Subtract the exponents:
10^7 - 10^3 = 10^4
Therefore, the quotient in scientific notation is 0.593 x 10^4 or 5.93 x 10^3.
4. Similar to the previous problems, to find the product of two numbers in scientific notation, you need to multiply the coefficients and add the exponents.
For the fourth problem, the coefficient is 4.0 and the exponent is 10^-2, and the coefficient is 5.2 and the exponent is 10^8.
Multiply the coefficients:
4.0 x 5.2 = 20.8
Add the exponents:
-2 + 8 = 6
Therefore, the product in scientific notation is 20.8 x 10^6.