Find the limit: as x approaches 0 lim((5/x)-(5/sin(x))
5/x - 5/sinx
= 5 * (sinx-x) / xsinx
now use l'Hospital's Rule
5(cosx-1)/(sinx + xcosx)
and again
-5sinx/(cosx+cosx-xsinx)
= 0/2
= 0
= 5 * (sinx-x) / xsinx
now use l'Hospital's Rule
5(cosx-1)/(sinx + xcosx)
and again
-5sinx/(cosx+cosx-xsinx)
= 0/2
= 0