3.50 g of NH4Cl is added to 18.8 g of water. Calculate the molality of the solution.
m = mols/kg solvent
m of the solution is twice that since +NH4Cl dissocites into NH4^+ & Cl^- (i.e., into two ions)
m of the solution is twice that since +NH4Cl dissocites into NH4^+ & Cl^- (i.e., into two ions)