(a) Find the potential at a distance of 0.920 cm from a proton. (Note: Assume a reference level of potential V = 0 at r = ∞.)
V
(b) What is the potential difference between two points that are 0.920 cm and 2.00 cm from a proton?
V
(c) Repeat parts (a) and (b) for an electron.
V
V
To find the potential at a distance from a proton, you can use the equation for the electric potential due to a point charge:
V = k*q/r
where V is the potential, k is the electrostatic constant (9 x 10^9 Nm^2/C^2), q is the charge of the proton or electron, and r is the distance from the charge.
(a) For a proton, q = +e, where e is the elementary charge (1.6 x 10^-19 C). Given that the distance is 0.920 cm = 0.0092 m, the equation becomes:
V = (9 x 10^9 Nm^2/C^2)*(1.6 x 10^-19 C) / 0.0092 m
By calculating this expression, you can find the potential at a distance of 0.920 cm from a proton.
(b) To find the potential difference between two points, you need to subtract the potential at one point from the potential at the other. Given that the distance between the points is 0.920 cm (0.0092 m) and 2.00 cm (0.02 m), use the equation from part (a) to calculate the potentials at each point. Then, subtract the potential at the first point from the potential at the second point to find the potential difference.
(c) For an electron, the charge is -e. Using the same approach as in part (a) and (b), you can calculate the potentials at a distance of 0.920 cm and 2.00 cm from an electron. Remember to use the charge of the electron (-e) in the calculation.