A projectile is fired from the surface of the Earth with a speed of 200 meters per second at an angle of 30°
above the horizontal. If the ground is level, what is the maximum height reached by the projectile?
(A) 5 m (B) 10 m (C) 500 m (D) 1,000 m (E) 2,000 m
Vo = 200m/s[30o]
Yo = 200*sin30 = 100 m/s.
Y^2 = Yo^2 + 2g*h
h = (Y^2-Yo^2)/2g
h=(0-100^2)/-20 = 500 m. g = -10 m/s^2
posted by Henry