The admission fee at an amusement park is 1.5 dollars for children and 4 dollars for adults. On a certain day, 294 people entered the park, and the admission fees collected totaled 716 dollars. How many children and how many adults were admitted
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The admission fee at an amusement park is 1.5 dollars for children and 4 dollars for adults. On a certain day, 315 people entered the park, and the admission fees collected totaled 960 dollars. How many children and how many adults were admitted?
To find the number of children and adults admitted, we can set up a system of equations based on the given information.
Let's assume "c" represents the number of children admitted and "a" represents the number of adults admitted.
From the given information, we can form two equations:
1. The total number of people admitted: c + a = 294
2. The total admission fees collected: 1.5c + 4a = 716
Now we need to solve this system of equations to find the values of "c" and "a."
We can start by multiplying the first equation by 1.5 to make the coefficients of "c" the same:
1.5(c + a) = 1.5(294)
1.5c + 1.5a = 441
Now we have a system of equations:
1.5c + 1.5a = 441
1.5c + 4a = 716
To eliminate the variable "c" from the equations, we can subtract the first equation from the second:
(1.5c + 4a) - (1.5c + 1.5a) = 716 - 441
1.5c - 1.5c + 4a - 1.5a = 275
2.5a = 275
a = 275 / 2.5
a = 110
Now we can substitute the value of "a" into the first equation:
c + 110 = 294
c = 294 - 110
c = 184
Therefore, 184 children and 110 adults were admitted to the amusement park.
number of adults --- x
number of children --- 294-x
solve for x:
4x + 1.5(294-x) = 716