Three times as many children as adults attended a concert Saturday. An adults ticket cost $7 and a child's ticket cost $3. The theater collected a total of $6000. How many people bought tickets.
a = 3c
7a+3c = 6000
so,
24c = 6000
get c, then a.
now you need a+c = ?
let a
let c
c =3a
3c +7a = 6000
3(3a) + 7a = 6000
9a +7a = 6000
16a = 6000
16a/16 =600/16
a = 375
c = 3a
c = 3(375) = 1125
people 1500
a = 3c
7a+ 3c = 6000
21c + 3c = 6000
24c = 6000
24c/24 =6000/24
c =250
a = 3c
a = 3(250) = 750
a+c = 1000
To solve this problem, we need to set up equations based on the given information.
Let's assume the number of adults who bought tickets is "x".
According to the problem, three times as many children attended the concert, so the number of children who bought tickets is 3x.
Now, we can calculate the total cost of the tickets sold. The cost of an adult's ticket is $7, so the total cost of adult tickets is 7x. Similarly, the cost of a child's ticket is $3, so the total cost of child tickets is 3 * 3x = 9x.
The problem tells us that the theater collected a total of $6000. So, we can set up the equation:
7x + 9x = 6000
Combining like terms, we get:
16x = 6000
To solve for x, the number of adults, we divide both sides of the equation by 16:
x = 6000 / 16
x = 375
So, the number of adults who bought tickets is 375. Since three times as many children attended the concert, the number of children who bought tickets is 3 * 375 = 1125.
Therefore, the total number of people who bought tickets for the concert is 375 adults + 1125 children = 1500 people.