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a 5.95 g sample of AgNO3 is reacted with excess BaCl2 according to the equation 2AgNO3 + BaCl2 yields 2AgCl + Ba(NO3)2 to give 3.17 g of AgCl. What is the percent yield of AgCl?

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Anonymous

  1. 2AgNO3 + BaCl2 ==> 2AgCl + Ba(NO3)2

    mols AgNO3 = grams/molar mass
    Using the coefficients in the balanced equation, convert mols AgNO3 to mols
    AgCl.
    g AgCl = mols AgCl x molar mass
    AgCl = ?. This is the theoretical yield; i.e., the yield if it were 100%.
    Then % yield = (3.17/theoret yield)*100 = ?

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    DrBob222

  2. 56

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    Anonymous

  4. 63.1506

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    Anonymous

  5. in a particular experiment to prepare a compound, the theoritical yield is 34.7 g. if the actual yield is 31. 2 g, what is the percentage yield?

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    Val

  6. The lost boy: Where are we?
    The monster: We are home wherever this is..
    but that doesn't matter.
    The lost boy: Why not
    The monster: Because we have no home

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    The lost boy

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