The electricity received at an electric substation has a potential difference of 2.80 x 10^5 V. If the required output is 440 V, what should be the ratio of the turns of the step-down transformer?
I know the transformer equation is:
Is/Ip = Vp/Vs = Np/Ns
"use that equation to get ratio Np/Ns"
I don't know what numbers to use, I know the numbers in the question but I'm still confused
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To find the ratio of turns in the step-down transformer, we can use the transformer equation:
Is/Ip = Vp/Vs = Np/Ns
Where:
Is = Secondary current (output current)
Ip = Primary current (input current)
Vp = Primary voltage (input voltage)
Vs = Secondary voltage (output voltage)
Np = Number of turns in the primary coil
Ns = Number of turns in the secondary coil
In this case, we are given Vp (primary voltage) as 2.80 x 10^5 V and Vs (secondary voltage) as 440 V.
To find the ratio of turns, we need to substitute the values of Vp and Vs into the transformer equation and solve for Np/Ns.
Vp/Vs = Np/Ns
Plugging in the values, we have:
(2.80 x 10^5 V) / (440 V) = Np / Ns
To simplify the equation, divide both sides by 440 V:
(2.80 x 10^5 V) / (440 V) = Np / Ns
(2.80 x 10^5 V) / (440 V) = Np / Ns
Now, cancel out the similar units:
(2.80 x 10^5) / (440) = Np / Ns
Simplifying the calculation:
(280000) / (440) = Np / Ns
636.36 = Np / Ns
Therefore, the ratio of turns in the step-down transformer is approximately 636.36 (or Np/Ns = 636.36).