y = ½ x^2 – x +3 for 1≤x≤6
(b) Calculate the mid- ordinates for 5 strips between x = 1 and x= 6, and hence use the mid-ordinate rule to approximate the area under the curve between x = 1, x = 6 and the x = axis.
(c) assuming that the area determined by integration to be the actual area, calculate the percentage error in using the mid-ordinate rule.
Did you not go back and check your post when you posted this question a few days back?
http://www.jiskha.com/display.cgi?id=1380495416posted by Reiny