Math
y = ½ x^2 – x +3 for 1≤x≤6
(b) Calculate the mid ordinates for 5 strips between x = 1 and x= 6, and hence use the midordinate rule to approximate the area under the curve between x = 1, x = 6 and the x = axis.
(c) assuming that the area determined by integration to be the actual area, calculate the percentage error in using the midordinate rule.
asked by
Kg

mmhh
Did you not go back and check your post when you posted this question a few days back?
http://www.jiskha.com/display.cgi?id=1380495416posted by Reiny
Respond to this Question
Similar Questions

Math
Graph y = ½ x^2 – x +3 for 0≤x≤6 Calculate the mid ordinates for 5 strips between x = 1 and x 6, and hence use the midordinate rule to approximate the area under the curve between x = 1, x = 6 and the x axis. 
math
Graph y = ½ x^2 – x +3 for 0≤x≤6 (b) Calculate the mid ordinates for 5 strips between x = 1 and x 6, and hence use the midordinate rule to approximate the area under the curve between x = 1, x = 6 and the x axis. 
math
Graph y = ½ x^2 – x +3 for 0≤x≤6 (b) Calculate the mid ordinates for 5 strips between x = 1 and x 6, and hence use the midordinate rule to approximate the area under the curve between x = 1, x = 6 and the x axis. 
math
y = ½ x^2 – x +3 for 0≤x≤6 (b) Calculate the mid ordinates for 5 strips between x = 1 and x= 6, and hence use the midordinate rule to approximate the area under the curve between x = 1, x = 6 and the x = axis. (c) 
Calculus
y = 1/2x^2x + 3 for 0_<x_<6. (b) Calculate the midordinates of 5 strips between x = 1 and x = 6, and hence use the mid ordinate rule to approximate the area under between x = 1, x = 6 and the xaxis. (c) Assuming that the 
PRE  CALCULUS
Eliminate the parameter t. Find a rectangular equation for the plane curve defined by the parametric equations. x = 6 cos t, y = 6 sin t; 0 ≤ t ≤ 2π A. x2  y2 = 6; 6 ≤ x ≤ 6 B. x2  y2 = 36; 6 
algebra 1 help please
4) a student score is 83 and 91 on her first two quizzes. write and solve a compound inequality to find possible values for a thord quiz score that would give anverage between 85 and 90. a. 85≤83+91+n/3 ≤90; 
calculus
Use the midpoint rule with n = 4 to approximate the area of the region bounded by y = x^3 and y = x.? I know how to use the midpoint rule to get the area under a curve but I'm confused on how to get the area between the two 
Calculus
Use the midpoint rule with n = 4 to approximate the area of the region bounded by y = x^3 and y = x. I just need to know how to use the midpoint rule when the area is between two curves instead of under a curve. Help please. 
Differentials (calc)
Solve the Poisson equation ∇^2u = sin(πx) for 0 ≤ x ≤ 1and 0 ≤ y ≤ 1 with boundary conditions u(x, 0) = x for 0 ≤ x ≤ 1/2, u(x, 0) = 1 − x for 1/2 ≤ x ≤ 1 and 0