the sides of a triangle are (x+2),(3x+1), and (x+7) find the value of x if the perimeter is 140cm
140 = x + 2 + 3x + 1 + x + 7
140 = 5x + 10
130 = 5x
26 = x
To find the value of x in a triangle with sides (x+2), (3x+1), and (x+7), given that the perimeter is 140 cm, we can set up an equation using the perimeter formula for a triangle.
Perimeter of a triangle = sum of all sides
Therefore, we have:
(x+2) + (3x+1) + (x+7) = 140
Now, let's simplify and solve for x:
4x + 10 = 140
4x = 140 - 10
4x = 130
x = 130/4
x = 32.5
So, the value of x is 32.5.
To find the value of x, we need to set up an equation using the given information and solve for x.
The perimeter of a triangle is the sum of the lengths of its sides. Therefore, we can write the equation:
(x + 2) + (3x + 1) + (x + 7) = 140
Now we simplify the equation:
5x + 10 = 140
Next, we isolate the variable x by subtracting 10 from both sides:
5x = 130
Finally, we solve for x by dividing both sides by 5:
x = 26
So, the value of x is 26.