If aluminum foil has a density of 2.70 g/ml, then how thick would be a 2.22 g sample of foilif it measures 5.0 cm on each side.
PLEASE SHOW WORK THX!
if the thickness is x cm, then since density = mass/volume, and 1ml = 1cm^3,
2.70 g/cm^3 = (2.22 g) / (25x cm^3)
Now just solve for x.
To find the thickness of the aluminum foil, we can use the formula for density:
Density = Mass / Volume
First, let's calculate the volume of the aluminum foil sample:
Volume = Length × Width × Height
Given that the foil measures 5.0 cm on each side, the height will represent the thickness we want to find. Therefore, the height is unknown and will be represented by "h".
Volume = 5.0 cm × 5.0 cm × h
Since the units of density are in g/ml, we need to convert the volume from cm³ to ml. Since 1 cm³ is equal to 1 ml, the volume will remain the same.
Now we can write the formula for density in terms of mass and volume:
2.70 g/ml = 2.22 g / (5.0 cm × 5.0 cm × h)
Next, we can solve for "h" by rearranging the formula:
h = 2.22 g / (2.70 g/ml × 25.0 cm²)
h = 2.22 g / 67.5 g/cm²
h = 0.0329 cm
Therefore, the thickness of the aluminum foil sample would be approximately 0.0329 cm.